The Let's Play Archive

Professor Layton and the Curious Village

by Dragonatrix

Part 31: The DLC III





[Music: Memories of St Mystere]



I can think of at least three ways to get this answer. Two of them are basically the same...






The only other possible idea I can think of is using the 3. By mirroring it, and then partially having it overlap with itself you can get an 8 out it giving 3, 8, 33, 38, 83 and 88.





All things considered, this one is pretty simple for what appears to be a complex maths puzzle.










Looking at the map layout, you can get either 3, 4 or 5 as the minimum for depending on which door you open at the end. Since we want the lowest number of doors opened, it's pretty obvious at that point which one is the right answer.










If it was on a step-by-step basis, the Cheetah would completely massacre the lion. It'd be almost halfway through the return trip by the time the lion was at the 100m mark.

As is, you have to do it in multiples of 6 instead while also keeping in mind their unique lengths per jump.






That 4 yards doesn't make
that much of a difference since they both end up back at the start at roughly the same time. It just takes the cheetah one jump more than the lion, which costs it the race in the end.





Apparently I underestimated this one or something, because people seemed to have a harder time with it than I expected.










Now this one surprised me. I was not expecting anyone over the age of about 8 to have trouble with this.




So, of course, when I get to it the first time I immediately link a screenshot of it on skype to a few friends because this is seriously a thing they are asking.



Not one of them got it right.


I don't even know anymore.






[Music: End Theme]



We might as well finish up the rest of the weekly puzzles at this point. There's only a handful left to go after all.



1. If you enter a room that has two doors, there is only one possible exit - the door you did not enter from - and you will not be able to pass through that room again. If a room has more than two doors, you have to pass through it again after exiting. Also, don't forget that you don't need to exit you room you end up in last. Which means...?

This one shouldn't be too tricky. There's a simple way of getting the answer after all.





1. Your task is to find which of the 12 iron balls weighs 100g. Since the others weigh 200g, you are trying to find one that weights half of that. How can you find something that looks the same but has half the weight?





1. The difference between A and B is three years, and the difference between B and C is two years. This means you can rule out the order BAC.





1. The contents and labels consist of three variations, RR, LL and LR. You have a very narrow range o options to choose from. Imagine the possible contents for each box and think about which one you should open.

I'm sure more people than not have done basically this exact same puzzle but not necessarily with shoes. I remember getting this well over 10 years ago, but with oranges and apples instead.



The last two (this one and the next) aren't version exclusive, but their numbers are. In the US version, this one is number 25 and the next one is 26. That's the only difference between the two.




1. Each student bows to the teacher and every other student. Including the teacher and the students, there are a total of 21 people. You may think that information is enough to go on, but make sure you've read the puzzle over carefully before you answer.





1. None of the wires should run off the sides of the panels, save for the areas where they connect to the light bulb and battery.









[Music: Professor Layton's Theme (Live)]



Since we've also beaten every puzzle in the base game, there's one last option in the Layton's Challenges section. To get access to it, you must beat all other 132 puzzles (120 in the main game, and the four other "houses").



You might think that these are therefore going to be hard.



You might then see the value of these and think again. You would be fairly wrong to do that.




1. Thinking in fractions is the key to success.
2. As the first hint suggested, don't try and calculate out hard numbers for this puzzle. Within the parentheses, you will encounter some odd fractions. Keep these in fraction form for the remainder of the problem. After all is said and done, as long as your numerator is 10 times larger than your denominator, you've found your answer.
3. The eight goes in the rightmost slot. Your goal is to arrange the numbers so that everything to the left of the equal sign calculates out to 40/4.

It might not be all that difficult once you know what you're doing, but it's certainly harder than just placing a few queens on a chess board.





1. The feuding parties have demanded that the land be divided into four identically sized properties. You'll have a much easier time achieving this if you start all your divisions from the middle of the large chunk of land.
2. If you find a group of houses or wells together, you know where one of your property lines needs to go. Now you just need to use a little logic to determine where the lines need to pass through.
3. The division lines for all four properties run through the center of the map. You'd do well to try dividing things up further after you've decided how to allot the four squares in the center of the map.